Monday, 29 September 2014

integration - Integral of int10fracdx1+e2x



I am trying to solve this integral and I need your suggestions.
I think about taking 1+e2x and setting it as t, but I don't know how to continue now.



10dx1+e2x


Thanks!


Answer




With the change of variable u=ex, you get
[0,1]dx1+e2x=[1,e]1u(1+u2)du


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