I am trying to solve this integral and I need your suggestions.
I think about taking 1+e2x and setting it as t, but I don't know how to continue now.
∫10dx1+e2x
Thanks!
Answer
With the change of variable u=ex, you get
∫[0,1]dx1+e2x=∫[1,e]1u(1+u2)du
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