|2eit−1|2
I don't understand how to work this out, I know if I had for example |2ti−1|2 then I would square the real and imaginary parts and add them to get the modulus squared, but here I have |2eit−1|2 and I don't understand what to do.
Any help would be much appreciated.
Answer
Considering that t is real, we use Euler's formula eiθ=cosθ+isinθ
|2eit−1|2=|2cost+2isint−1|2=(2cost−1)2+(2sint)2
This evaluates as (5−4cost) and as you can see, the value is dependent on t which is the argument of the complex number eit in polar form.
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