Suppose f:A→B is a bijection. For A,B⊆C. Show that a bijective map h:C∖A→C∖B exists.
I'm not sure how to proceed, may I have a hint please?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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