Sunday, 10 January 2016

real analysis - Is the sequence of functions fn(x)=nxenx2 uniformly bounded on the interval [0,1]?



Is the sequence of functions fn(x)=nxenx2 uniformly bounded on the interval [0,1]?



I have been trying to figure out if it is uniformly bounded on [0,1] but am having trouble verfiying it. I know that by definition if for ALL x[0,1] and ALL n I can show that fn(x) is bounded above by some constant, I am good to go. But, it seems that the x portion of the function is bounded ok but the n part may not be. Does anyone have a good way of showing if it is uniformly bounded? thank you!


Answer




Let's find the maximum of fn(x): Notice that fn(x)=nenx22n2x2enx2, so fn(x)=0n=2n2x2x=1/2n, and this is in [0,1].



Since fn(1/2n)=n1/2nen(1/2n)=n/2e1/2, then (fn) is not uniformly bounded.


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