Is the sequence of functions fn(x)=nxe−nx2 uniformly bounded on the interval [0,1]?
I have been trying to figure out if it is uniformly bounded on [0,1] but am having trouble verfiying it. I know that by definition if for ALL x∈[0,1] and ALL n I can show that fn(x) is bounded above by some constant, I am good to go. But, it seems that the x portion of the function is bounded ok but the n part may not be. Does anyone have a good way of showing if it is uniformly bounded? thank you!
Answer
Let's find the maximum of fn(x): Notice that f′n(x)=ne−nx2−2n2x2e−nx2, so f′n(x)=0⟺n=2n2x2⟺x=√1/2n, and this is in [0,1].
Since fn(√1/2n)=n√1/2ne−n(1/2n)=√n/2e−1/2→∞, then (fn) is not uniformly bounded.
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