I'm pretty sure a−1∑i=1i=a(a−1)2 using the relationship n∑i=1i=n(n+1)2.
It looks similar to n∑i=ai=(n+a)(n−a+1)2 but I'm not sure how or why doesn∑i=ai=(n+a)(n−a+1)2?
How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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