Tuesday, 21 November 2017

trigonometry - (sintheta+costheta)2=1+sin2theta



49) (sinθ+cosθ)2=1+sin2θ
Left Side:
(sinθ+cosθ)2=sin2θ+2ccosθsinθ+cos2θ=1+2cosθsinθ
This can either be 1 or I can power reduce it. I don't know.



Right Side:
1+sin2θ=1+2sinθcosθ



Thank you!


Answer



Open parentheses and use:



(1)sin2x+cos2x=1



(2)sin2x=2sinxcosx


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