Sunday 27 July 2014

calculus - continuity at zero implies continuity everywhere


Suppose $f(x)$ is defined on the entire line and continuous at the
origin with the property that $f(\alpha+\beta) = f(\alpha) + f(\beta)$
where $\alpha,\beta \in \mathbb{R}$. Prove that $f(x)$ must be
continuous at every point $x=a$.





Try:



First notice that $f(0) = f(0+0)=f(0)+f(0)=2f(0) \implies f(0)=0$. Since $f$ continuous at zero, then $\lim_{x \to 0} f(x) = f(0) = 0$. Next, let $a $ be arbitary real number. Then,



$$ \lim_{ x \to a} f(x) = \lim_{x \to a} f(x-a)+f(a)=_{h = x-a} \lim_{h \to 0} f(h) + f(a) = 0 + f(a)=f(a)$$



So f is continuous everywhere.




Is this a correct solution?

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