$\operatorname{Aut}(K_4 \times \mathbb{Z}_2)$ is isomorphic to group of order 168.
I don't know how to start to find an element of $\operatorname{Aut}(K_4 \times \mathbb{Z}_2)$ such that his order divides $3$ (non-trivial).
I appreciate your help.
$\operatorname{Aut}(K_4 \times \mathbb{Z}_2)$ is isomorphic to group of order 168.
I don't know how to start to find an element of $\operatorname{Aut}(K_4 \times \mathbb{Z}_2)$ such that his order divides $3$ (non-trivial).
I appreciate your help.
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