How do i evaluate :
∞∑n=1n3xn−1
The answer is supposed to be: (according to wolfram alpha)
x2+4x+1(x−1)4
I have only learned to to this for simpler geometric sums.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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