Prove 1+12+14+...+12n=2−12n for all positive integers n.
My approach was to add 12n+1 to both sides for the induction step. However, I got lost in the algebra and could not figure out the rest of the proof. Any help would be greatly appreciated.
Thank you in advance.
Answer
Hint
if we add 12n+1 to the right side, we get
2−12n+12n+1
=2−22n+1+12n+1
2−12n+1
qed.
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