Prove $1 + \frac{1}{2} + \frac{1}{4} + ... + \frac{1}{2^{n}} = 2 - \frac{1}{2^{n}}$ for all positive integers $n$.
My approach was to add $\frac{1}{2^{n + 1}}$ to both sides for the induction step. However, I got lost in the algebra and could not figure out the rest of the proof. Any help would be greatly appreciated.
Thank you in advance.
Answer
Hint
if we add $\frac{1}{2^{n+1}}$ to the right side, we get
$$2-\frac{1}{2^n}+\frac{1}{2^{n+1}}$$
$$=2-\frac{2}{2^{n+1}}+\frac{1}{2^{n+1}}$$
$$2-\frac{1}{2^{n+1}}$$
qed.
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