Wednesday, 3 September 2014

calculus - limxto0fracsinxxx2 without L'Hospital or Taylor



It is easy to see that limx0sinxxx2=0,

but I can't figure out for the life of me how to argue without using L'Hospital or Taylor. Any ideas?


Answer



In THIS ANSWER, I used the integral definition of the arcsine function to show that for 0xπ/2, we have the inequalities




xcos(x)sin(x)x



Using the trigonometric identity 1cos(x)=2sin2(x/2), we see from (1) that



2x(sin2(x/2)x2)14sin(x)xx20



Applying the squeeze theorem to (2) yields the coveted limit





limx0sin(x)xx2=0



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