Seems that it is possible to get using Wolfram Alpha online calculator the limit as $s$ tends to zero of the derivative of the Riemann Zeta function $$\lim_{s\to0}\zeta^{(k)}(s).\tag{1}$$
For example write lim RiemannZeta'''(s), as s-->0
or lim RiemannZeta''''(s), as s-->0
Question. Imagine that one need to justify a limit of previous kind, say us $$\lim_{s\to0}\zeta^{(iv)}(s),\tag{2}$$
what is the way to get such closed-form in terms of constants? Isn't required the full expression, only is required how to start with the evaluation of this kind of limit, in this example say us $(2)$. Many thanks.
I am asking about a sketch to get the limit, for example what formula I need and what calculations will be need. Thus I don't require all details, since I think that it is tedious, and if you known it from the literature please refer it answering this as a reference request.
Answer
"Formulas for Higher Derivatives of the Zeta Function," by Tom M. Apostol, Math. Comp., Vol. 44, Num 169, January 1985, pp.223-232. According to the abstract, a closed form formula is given for $\zeta^{(k)}(0)$ is given, along with along with numerical values to 15D for $k=0\dots 18$
I found this by Googling "Higher derivatives of the zeta function," and then looking at the paper on JSTOR.
No comments:
Post a Comment