I have this basic problem:
In a farm, X animals are added to the farm. These animals gain weight according to the equation: 500−2X gr. Which interval of animals can the farm take, if the total weight gain is greater than 30,600 Kg?
Original (Spanish - Español):
En un criadero de cuyes se integran x cuyes, si se tiene presente que los cuyes ganan peso en promedio de (500−2x) gramos. ¿Qué intervalo de cuyes puede aceptar esta granja si la ganancia total de peso de los cuyes es mayor a 30600 Kg?
Step 1:
Total animals: x.
Weigthgain = (500−2x) gr.
TotalWeightgain > 30600(1000) converting kg to gr.
Step 2:
x(500−2x)>30600000
Step 3:
0>2x2−500x+30600000
Step 4:
x=−(−500)+−2√(−500)2−4(2)(30600000)2(2)
But as you can see, the sqrt is negative. So It does not exist.
What should be the next step?
No comments:
Post a Comment