Sunday, 24 May 2015

elementary number theory - Prove that for x3=3 there isn't rational solution




Prove that for x3=3 there isn't rational solution




What I did:



Suppose x=u/v is solution




(uv)3=3



Let's take third root from both sides:



uv=33



and 33 is irrationl ,



my problem is this "and 33 is irrationl " is it well known that this number is irrationl? same as π?




or maybe there is another why to prove it?


Answer



Just start off my assuming (u,v)=1 i.e the fraction is fully reduced. Then it follows that;
u3=3v33u33uu=3M



Therefore (3M)3=27M3=3v3 and so 9v3 which implies 3v3 and so (v,u)1 which is a contradiction.


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