Friday, 29 May 2015

calculus - Proving that the limit of rootnofa1n+a2n+...+akn is max(a1,...ak)






Prove that:
limnna1n+a2n+...+akn=max{a1,a2...ak}





I am familiar with the theorem which says that if
limnanan1=L



then,
limnnan=L



So, I tried evaluating the expreesion:
a1n+a2n+...+akna1n1+a2n1+...+akn1



but pretty much got stuck here. Is this the right path to go?


Answer



nanmaxnan1++anknkanmax



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