Tuesday, 19 May 2015

How do I define probability space (Omega,mathcalF,mathbbP) for continuous random variable?



I need to mathematically define the probability space (Ω,F,P) of continuous random variable X. I also need to define the continuous random variable X itself. Problem is... I don't really know how.



It is known that X has the following probability density function fX:R[0,49]:




fX(x)={19(3+2xx2):0x30:x<0x>3



and its plot:



enter image description here



Also, the cumulative distribution function of X is FX:R[0,1] and is defined as:



FX(x)={0:x<019(3x+x213x3):x0x31:x>3




and its plot:



enter image description here



(please see this thread where I calculated CDF for reference)






I suppose:




X:ΩR



and sample space:



Ω=R



How can I define F and P, that are the quantities of probability space (Ω,F,P)? I was thinking:



P:F[0,1]P(Ω)=1




I am jumping into statistics/probability and I am lacking the theoretical knowledge. Truth be speaking, the wikipedia definition of probability space for continuous random variable is too difficult to grasp for me.



Thanks!


Answer



It is a bit weird to ask for a probability space if the probability distribution is already there and is completely at hand. So I think this is just some theoretical question to test you. After all students in probability theory must be able to place the "probability things" they meet in the confidential context of a probability space.



In such case the easyest way is the following.



Just take (Ω=R,F=B(R),P) as probability space where B(R) denotes the σ-algebra of Borel subsets of R and where probability measure P is prescribed by: BBfX(x)dx




Then as random variable X:ΩR you can take the identity on R.



The random variable induces a distribution denoted as PX that is characterized by PX(B)=P(XB)=P(X1(B)) for every BB(R)



Now observe that - because X is the identity - we have X1(B)=B so that we end up with:PX(B)=BfX(x)dx for every BB(R)

as it should. Actually in this special construction we have:(Ω,F,P)=(R,B(R),PX) together with X:ΩR prescribed by ωω



Above we created a probability space together with a measurable function ΩR such that the induced distribution on (R,B(R)) is the one that is described in your question.







PS: As soon as you are well informed about probability spaces then in a certain sense you can forget about them again. See this question to gain some understanding about what I mean to say.


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...