For every c∈[0;2] determine whether the sequence {an}n≥1 which is defined as follows:
a1=c, an+1=1+(an−1)217 for n≥1
is monotonic for sufficiently large n, and determine whether its limit exits and if it exists, give its value.
I have no idea what to do with this problem. I was able to see that an+1−an is a quadratic function and I also found ot that limit, if exists, is equal to either 1 or 18 (that's beacause if an id convergent to g then every subsequence is also convergent to g). So how to determine the limit for every c∈[0;2]?
Answer
an+1−an=17+(an−1)2−17an17=(an−1)(an−18)17
This number is ≤0 for an∈[1,2] and >0 for an∈[0,1). But observe that even if a0<1 then a2>1. So, the sequence eventually decreases while it is bounded by 0.
You already got the possible limits and you can discard 18 because the sequence is always smaller than say 2.
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