Sunday, 14 May 2017

How to apply modular division correctly?




As described on Wikipedia:
$$\frac{a}{b} \bmod{n} = \left((a \bmod{n})(b^{-1} \bmod n)\right) \bmod n$$




When I apply this formula to the case $(1023/3) \bmod 7$:
$$\begin{align*}
(1023/3) \bmod 7 &= \left((1023 \bmod 7)((1/3) \bmod 7)\right) \bmod 7 \\
&= ( 1 \cdot (1/3)) \mod 7 \\
&= ( 1/3) \mod 7 \\
&= 1/3
\end{align*}
$$
However, the real answer should be $(341) \bmod 7 = \mathbf{5}$.




What am I missing? How do you find $(a/b) \bmod n$ correctly?


Answer



$\frac{1}{3}\mod 7 = 3^{-1}\mod 7$



You need to solve below for finding $3^{-1}\mod 7$ : $$3x\equiv 1\pmod 7$$



Find an integer $x$ that satisfies the above congruence


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