Perhaps everybody has heard of the Stirling's approximation, namely:
Γ(z)≈√2πz(ze)z
Thus (the very basic example):
Γ(12z)≈√4πz(√z2e)z
My question is: how does one obtain the lower and upper bound for the Gamma function using the Stirling's approximation? I've heard that √4πz(√z2e)z−1<Γ(12z)<√4πz(√z2e)z+1 is a very "ugly" and unproper way (moreover it doesn't always work). So what's the best way to obtain the lower and upper bound?
Monday, 15 May 2017
inequality - Lower and upper bound of the Stirling's approximation
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