Please help me to prove limn→∞an=0 then limn→∞1an=∞
Please give me a hint, not a full solution.
I know how to prove an→∞⇒1an→0, but not the other way around.
The original problem:
Given ∀a∈{an},a<0 and limn→∞an=0 prove: limn→∞1an=−∞
Answer
Since {an} is negative and an→0, for each M∈N there exists N such that $-\frac{1}{M}
Therefore 1an<−M for all n≥N, which implies that 1an→−∞.
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