algebra precalculus - How do I show that $sqrt{5+sqrt{24}} = sqrt{3}+sqrt{2}$

According to wolfram alpha this is true: $\sqrt{5+\sqrt{24}} = \sqrt{3}+\sqrt{2}$

But how do you show this? I know of no rules that works with addition inside square roots.

I noticed I could do this:

$\sqrt{24} = 2\sqrt{3}\sqrt{2}$

But I still don't see how I should show this since $\sqrt{5+2\sqrt{3}\sqrt{2}} = \sqrt{3}+\sqrt{2}$ still contains that addition

Answer

Hint: Since they are both positive numbers, they are equal if, and only if, their squares are equal.