Show that limn→∞{(n!)1/nn}=1e
What I did is to let Un=(n!)1nn and Un+1=(n+1)!1n+1n+1. Then
Un+1Un=(n+1)!1n+1n+1(n!)1nn
Next I just got stuck. Am I on the right track, or am I wrong doing this type of sequence?
Answer
Let vn=n!nn then vn+1vn=(n+1)!(n+1)n+1⋅nnn!=nn(n+1)n=1(1+1n)n→1e
hence n√n!n=n√vn→1e.
No comments:
Post a Comment