Friday, 15 February 2019

real analysis - Show that limlimitsntoinftyfrac(n!)1/nn=frac1e





Show that limn{(n!)1/nn}=1e




What I did is to let Un=(n!)1nn and Un+1=(n+1)!1n+1n+1. Then



Un+1Un=(n+1)!1n+1n+1(n!)1nn




Next I just got stuck. Am I on the right track, or am I wrong doing this type of sequence?


Answer



Let vn=n!nn then vn+1vn=(n+1)!(n+1)n+1nnn!=nn(n+1)n=1(1+1n)n1e

hence nn!n=nvn1e.


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