Tuesday, 26 February 2019

calculus - Find the value of : limntoinftyleft(left(sum2nk=n+12sqrt[2k]2ksqrt[k]kright)nright)



Find limn((2nk=n+122k2kkk)n).




I have tried rewriting the sum in a clever way, applying the Mean Value Theorem or Stolz-Cesaro Lemma somehow but haven't found anything fruitful.



Can someone please share a hint/trick to evaluate this?



Thank you.


Answer



Hint: use the power series expansion
yy=exp(logyy)=1+logyy+O((logy)2y2)



(or upper and lower bounds for exp() that express the same idea).



Reality check: the answer is a tidy number about 4% less than 12.


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...