Find limn→∞((2n∑k=n+122k√2k−k√k)−n).
I have tried rewriting the sum in a clever way, applying the Mean Value Theorem or Stolz-Cesaro Lemma somehow but haven't found anything fruitful.
Can someone please share a hint/trick to evaluate this?
Thank you.
Answer
Hint: use the power series expansion
y√y=exp(logyy)=1+logyy+O((logy)2y2)
(or upper and lower bounds for exp(⋅) that express the same idea).
Reality check: the answer is a tidy number about 4% less than 12.
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