Let g:(1,+∞)→R, differentiable, such that |g′(x)|≤1x for all x>1. Show that
limx→+∞(g(x+√x)−g(x))=0.
Seems like the mean value theorem is useful. However, not sure how to prove the fact.
Remark:
The hints says that only proving
limx→+∞|g(x+√x)−g(x)|=0.
won't suffice.
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