The question is to prove the inequality 1n+1≤ln(1+1n)≤1n∀n≥1,n∈N
I tried using Taylor expansion but couldn't figure out anything. Any ideas? Thanks.
Answer
Suppose $n
Integrate this with respect to x, from n to n+1. Then
1n+1<log(n+1)−logn<1n,
and the middle is log(1+1n).
No comments:
Post a Comment