Thursday, 7 November 2013

why using irriducible polinomial for galois field?



To construct the finite field GF(23) we need to choose an irreducible polynomial of degree 3. Why we should choose an irreducible polynomial? I don't understand this lemma


Answer




If K is any field and P is a reducible polynomial in K[X], then K[X]/(P) is not an integral domain, and so certainly not a field. Indeed if P=QR with non-constant Q,RK[X], then the images of Q and R in K[X]/(P) are nonzero (since their degrees are striclty less than P, they cannot reduce modulo P). But the product of those images is the image of P, which by definition is 0K[X]/(P), so those images are zero divisors in K[X]/(P). This is why one should always choose irreducible polynomials to construct extension fields.


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