I have to calculate the following limit:
limn→∞(1√n2+1+1√n2+2+...+1√n2+n)
I believe the limit equals 1, and I think I can prove it with the squeeze theorem, but I don't really know how.
Any help is appreciated, I'd like to receive some hints if possible.
Thanks!
Answer
For every n>0,
n√n2+n≤1√n2+1+1√n2+2+⋯+1√n2+n≤n√n2+1
Can you continue with Squeeze theorem?
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