Wednesday, 13 May 2015

calculus - Showing that the function given by $f(x,y)=frac{xy}{sqrt{x^2+y^2}}$ and $f(0,0)=0$ is continuous but not differentiable

Let
$$

f(x,y) =
\begin{cases}
\dfrac{xy}{\sqrt{x^2+y^2}} & \text{if $(x,y)\neq(0,0)$ } \\[2ex]
0 & \text{if $(x,y)=(0,0)$ } \\
\end{cases}
$$
Show that this function is continuous but not differentiable at $(0,0),$ although it has both partial derivatives existing there.



I can show this function is continous and the partial derivatives exist. But how can I show that this function is not differentiable?




Is showing that the function is differentiable similar to showing that a derivative exists?

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...