Find this limit without l'Hopital rule : limx→+∞x(1+sinx)x−√1+x2
I tried much but can't get any progress!
Answer
The limit does not exist. Multiply top and bottom by x+\sqrt{1+x^2}. The bottom becomes -1. As to the new top, it is very big if \sin x is not close to -1. However, there are arbitrarily large x such that \sin x=-1.
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