Monday, 22 June 2015

logarithms - Why is ax=exloga?



Why is ax=exloga, where a is a constant?




From my research, I understand that the the natural log of a number is the constant you get when you differentiate the function of that number raised to the power x. For example, if we differentiate the function 2x, we get 2log2. I also understand that the natural log of e is just 1. But I cannot connect the dots here.



I would really appreciate an intuitive explanation of why we can write a number raised to a power as e raised to (the power x the natural logarithm of the number)?


Answer



I think we can agree that



a=eloga



which arises from one of the properties of the logarithm. Therefore, it’s sufficient to say that




ax=elogax



But one of the properties of the logarithm also dictates that



logax=xloga



Therefore



ax=exloga


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...