When I tried to find the limit of
limx→0+e−1xx2
by applying L'Hopital's Rule the order of denominator would increase. What else can I do for it?
Answer
Let y=1x, then x=1y⇒L=limy→+∞y2ey=limy→+∞2yey=limy→+∞2ey=0
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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