I have a trouble with a integral:
Using this Laplace trasform equation:
∫∞0F(u)g(u)du=∫∞0f(u)G(u)duL[f(t)]=F(s)L[g(t)]=G(s)
Applying to compute this integral:
I=∫∞0sin4xx3dx
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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