An even polynomial with a constant term of 1 will have no real roots if the coefficients of the powers (the c's below) are non-negative. So
1+c2x2+c4x4+c6x6
has no real roots. Is there a general way to parameterize an nth order polynomial with a constant term of 1 so that it has no real roots? I know that the above conditions (even powers, with non-negative coefficients) are more restrictive than necessary. The application is fitting (x,y) data where y is always positive with a polynomial in x.
Answer
Let p(x)=1+c1+…cn. Since p(0)=1>0, if p does not have real roots, it must be positive. This implies cn>0 (otherwise there would be a positive root) and n even (otherwise there would be a negative root.) Applying Descartes rule of signs to p(x) and p(−x) we get the following necessary condition: the sequences of coefficients
1,c1,c2,c3,…,cn,and1,−c1,c2,−c3,…,cn
must have an even number of sign changes.
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