I am finding a conformal map from $\mathbb C - [-1, 1]$ onto $\mathbb C - \overline{\mathbb D}$, where $\mathbb D$ denote the open unit disk.
The hint of this exercise says that I could make use of square root $\sqrt{\quad}$ to construct such a function, but I can't figure out what's the relation here since I don't think $\sqrt{\quad}$ can be defined on the domain.
Could anybody give me some further hints?
Rmk: By conformal we means that the desired function $f$ is holomorphic with nowhere vanishing derivative but not necessarily bijective.
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