Friday, 26 June 2015

linear algebra - Show that the matrix (cbfA)n=cnbfAn

I am being asked to show that given a square, invertible matrix A, then (cA)n=cnAn for all non zero c's in R.



I've tried just sort of writing down the definition of invertibility and playing a bit with that but it doesn't seem to be working. I think perhaps there's some basic property I'm missing.




Thanks for any help.

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