algebra precalculus - Proving $6 secphi tanphi = frac{3}{1-sinphi} - frac{3}{1+sin phi}$

$$6 \sec\phi \tan\phi = \frac{3}{1-\sin\phi} - \frac{3}{1+\sin \phi}$$

I can't seem to figure out how to prove this.

Whenever I try to prove the left side, I end up with $\frac{6\sin\theta}{\cos\theta}$, which I think might be right.

As for the right side, I get confused with the denominators and what to do with them. I know if I square root $1-\sin\phi$, I'll get a Pythagorean identity, but then I don't know where to go from there.

Please help me with a step-by-step guide. I really want to learn how to do this.