So here is the question and the work to solve it, but I have no idea how one knows to do the first step or what the first step is...
(6−i√12)12=[√48(cos(π6)−isin(π6))]12=(√48)12[cos(12π6)−isin(12π6)]=486
Answer
Step 1 Write your number in polar coordinates, i.e. z=r(cost+isint).
Step 2 Use De Moivre's theorem, that (cost+isint)n=cosnt+isinnt.
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