I'm stuck on the question ∑∞k=0(13)k+3
I know that ∑∞k=0(13)k is solved by using ∑∞k=0ak= 11−a and the answer is 32
So is there a way I could apply that to the above question or is there a different way to approach the problem?
Answer
n∑k=0(13)k+3=133n∑k=0(13)k→12711−13=12732=118
No comments:
Post a Comment