Prove if $n\mid ab$, then $n\mid [\gcd(a,n)\times \gcd(b,n)]$
So I started by letting $d=\gcd(a,n)$ and $e=\gcd(b,n)$.
Then we have $x,y,w,z$ so that $dx=a$, $ey=b$,$dw=ez=n$
and we also have $s$ so that $ns=ab$
or $ns=dexy$.
what I want is $n\mid de$, but I'm only getting to $n\mid de(xy)$ since I cannot prove that $s/(xy)$ is an integer.
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