If the series ∑∞n=1an converges absolutely
and ank is sub sequence of an
does the series ∑∞n=1ank also always converge ?
Since I failed to found any counter-example,
and the only connection between absolutely convergence of ∑∞n=1an and convergence of ∑∞n=1ank in my textbook is this theorem:
the series ∑∞n=1an converges absolutely iif the series of positive and negative members of an converges,
I concluded that my proof must be somehow connected to this theorem.
In this stage I arrived to the dead-end.
Could you please give me some hint how to deal with this question ?
Thanks.
Answer
Yes, it does. Since {nk:k∈N}⊆{n:n∈N}, we see that
∑k|ank|≤∑n|an|<∞
So the relevant sum is, in fact, absolutely convergent.
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