Tuesday, 28 June 2016

real analysis - The series sumin=1nftyan converges absolutely, does the series sumin=1nftyank converge?



If the series n=1an converges absolutely



and ank is sub sequence of an




does the series n=1ank also always converge ?



Since I failed to found any counter-example,
and the only connection between absolutely convergence of n=1an and convergence of n=1ank in my textbook is this theorem:
the series n=1an converges absolutely iif the series of positive and negative members of an converges,
I concluded that my proof must be somehow connected to this theorem.



In this stage I arrived to the dead-end.




Could you please give me some hint how to deal with this question ?



Thanks.


Answer



Yes, it does. Since {nk:kN}{n:nN}, we see that



k|ank|n|an|<



So the relevant sum is, in fact, absolutely convergent.


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