Say I roll two twenty-sided dice and always take the higher number rolled, and dispose of the lower number. What are the percent chances of rolling each number on the die?
I tried the equations in this question: What is the average of rolling two dice and only taking the value of the higher dice roll?
But for some reason I couldn't get the correct answer.
Answer
There is $1$ way to get a $1$, namely $(1,1)$
There are $3$ ways to get a $2$, namely $(1,2),(2,2),(2,1)$
There are $5$ ways to get a $3$, namely $(1,3),(2,3),(3,3),(3,2),(3,1)$
In general there are $2k-1$ ways to get a $k$.
The basic percentage unit is $0.25\%$, so the percentage chance to throw a $k$ is $(\frac{2k-1}{4})\%$, e.g. for $k=5$ the percentage is $1.25\%$.
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