Say I roll two twenty-sided dice and always take the higher number rolled, and dispose of the lower number. What are the percent chances of rolling each number on the die?
I tried the equations in this question: What is the average of rolling two dice and only taking the value of the higher dice roll?
But for some reason I couldn't get the correct answer.
Answer
There is 1 way to get a 1, namely (1,1)
There are 3 ways to get a 2, namely (1,2),(2,2),(2,1)
There are 5 ways to get a 3, namely (1,3),(2,3),(3,3),(3,2),(3,1)
In general there are 2k−1 ways to get a k.
The basic percentage unit is 0.25%, so the percentage chance to throw a k is (2k−14)%, e.g. for k=5 the percentage is 1.25%.
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