I can't seem to see the how the expression was simplified from
−ln(2)2x(12)x2+1
to
−ln(2)x(12)x2
I am sure I am missing something, and it is probably a simple solution.
Please help.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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