I can't seem to see the how the expression was simplified from
$$-\ln(2)2x\left(\frac{1}{2}\right)^{x^2+1}$$
to
$$-\ln(2)x\left(\frac{1}{2}\right)^{x^2}$$
I am sure I am missing something, and it is probably a simple solution.
Please help.
I can't seem to see the how the expression was simplified from
$$-\ln(2)2x\left(\frac{1}{2}\right)^{x^2+1}$$
to
$$-\ln(2)x\left(\frac{1}{2}\right)^{x^2}$$
I am sure I am missing something, and it is probably a simple solution.
Please help.
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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