limx→∞√4x2+4−(2x+2)
So, I have an intermediate form of ∞−∞ and I tried multiplying by the conjugate; however, I seem to be left with another intermediate form of ∞∞ and wasn't sure what else to to do. Is there anything else I can do other than L'Hopital's rule?
Answer
√4x2+4−(2x+2)=(√4x2+4−(2x+2))(√4x2+4+(2x+2))√4x2+4+(2x+2)=4x2+4−4(x+1)2√4x2+4+(2x+2)=−8x√4x2+4+(2x+2)=−8√4+4/x2+2+2/x
Now take the limit as x→∞ to get the limit as −2.
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