Monday, 24 April 2017

calculus - Find the value of : limxtoinftysqrt4x2+4(2x+2)












limx4x2+4(2x+2)



So, I have an intermediate form of and I tried multiplying by the conjugate; however, I seem to be left with another intermediate form of and wasn't sure what else to to do. Is there anything else I can do other than L'Hopital's rule?


Answer



4x2+4(2x+2)=(4x2+4(2x+2))(4x2+4+(2x+2))4x2+4+(2x+2)=4x2+44(x+1)24x2+4+(2x+2)=8x4x2+4+(2x+2)=84+4/x2+2+2/x



Now take the limit as x to get the limit as 2.


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