I am trying to evaluate the following integral:
∫√x2+1x4dx
I tried the trigonometric substitution: u=tan(x). Generally, The whole integral needs two substitutions: u=tan(x) then v=sin(u). In order to get rid of trigonometric functions, one needs to know that: sin(arctan(x))=x√x2+1
My question is: What is the fast substitution that leads to the answer without passing by the above steps?
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