Saturday, 29 April 2017

elementary number theory - Calculate 121199mod300

Using Fermat's little theorem I proved that





121^{199} = 121^{39} \mod 300




(as \phi(300) is 80) but I don't think I can leave it like this.
My question being how can I solve 121^{39}\hspace{-3mm}\mod 300. Any ideas, suggestions?

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