Check the series whether it is convergent /divergent?
$$\sum\limits_{n=0}^{\infty}\frac{(3i)^{2n+1}}{(2n+1)!}$$
I was thinking about the Taylor series but could not get its,,,,how to expand
I think the series is divergent by D'Alembert ratio test.
Am I right? Can you verify it and tell the solution, please? I would be grateful.
Thanks in advance.
Answer
Not only does your series converge by the ratio test (see the previous two answers), it can be summed.
As
$$\sinh (z) = \sum_{n = 1}^\infty \frac{z^{2n + 1}}{(2n + 1)!}, \quad z \in \mathbb{C},$$
setting $z = 3i$ we have
$$\sum_{n = 0}^\infty \frac{(3i)^{2n + 1}}{(2n + 1)!} = \sinh (3i) = i \sin (3).$$
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