Monday, 7 October 2013

calculus - How do I find this limit: limxtoinftysqrtx43x21x2




limxx43x21x2



The answer is
32


according to Wolfram alpha.


Answer



I would consider limxx43x21x2



as limxx43x21x21



Then multiply x43x21+x2 top and bottom to get rid of the ridiculous looking square root sign on the top. Then bingo!


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