Need to find limn→∞(an1+⋯+ank)1n Where a1≥⋯≥ak≥0
I thought about Cauchy Theorem on limit limn→∞a1+⋯+ann=liman and something like what happen if all ai=0 or a1=⋯=ak, but may be something I am thinking wrong?
Maybe it is too simple but I am not getting it; please help.
Answer
Note that
a1=[an1]1/n≤[an1+⋯+ank]1/n≤[kan1]1/n=k1/na1
and apply squeeze theorem.
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