Thursday, 10 October 2013

Properties of the finite field with 729 elements



I am trying to solve the following problem: let K be a finite field with 729 elements.




  • How many αK make K=α?

  • How many fields E are such that K|E is a field extension? What number of elements have each?

  • How many βK satisfy K=F3[β]?

  • How many irreducible polynomials of degree 2, 3 and 6 are in F3[t]?




And I have argued as follows:



Since K has 729 elements, and 729 is 36, it follows KF36, the finite field with 36 elements, so every E such that K|E is field extension needs to satisfy |E|=pk with k|6, so there are, up to isomorphism, 4 field extensions of the form EK, that are F3|K, F32|K, F33|K and F36|K.



Also, since K is cyclic of order pn1, K=u for some uK, and each element αK can be written α=uk. For αK to satisfy K=α, it is needed to be gcd, since
\mathrm{order}(u^k) = \frac{\mathrm{order}(u)}{\gcd(k,\mathrm{order}(u))}
so the number of \alpha's with this property is \varphi(728) = 288.




This should give all the elements such that K=\mathbb F_3[\alpha], since every element \beta\in K except 0 satisfies \beta = \alpha^{k}\in \mathbb F_3[\alpha] and |K|=|\mathbb F_3[\alpha]| (is this right?)



For the last, I would only know how to calculate the number of irreducible and monic polynomials, but I don't know how to calculate the whole number of irreducible polynomials with those degrees.



I would appreciate some hints or help. Thanks in advance.


Answer



Most of it looks good, except for the last part. You don't need \beta to be a generator for \mathbb{F}_{3}[\beta] = \mathbb{F}_{3}[\alpha]. What you need is for the minimal polynomial of \beta over \mathbb{F}_{3} to have degree 6. Equivalently, you need \beta not to be in any proper subfield of K.



To count the number of irreducible polynomials, use the fact that the irreducible polynomials of these degrees in \mathbb{F}_{3}[t] are going to factor completely in K. For example, an irreducible polynomial of degree 2 is going to have two distinct conjugate roots in \mathbb{F}_{3^{2}} \setminus \mathbb{F}_{3}, so there should be (9-3)/2 of them (that are monic).


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