Suppose g(x)=a1x+a2x2+...+akxk and f(x)=bjxj where a1,a2...ak>0 , j∈{1,2.....,k−1}, bj>0 and x≥0.
Intuitively, I think they can have at most two intersections. Is that correct?
Well, the answer is it has two positive roots by Descartes' rule of signs. Thanks for your help!
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